今天遇到一个非常郁闷的问题,先看下面代码
这个是JSP页面取值代码:
<td width="102" height="30" align="left"><bean:write name="regediter" property="username"/></td>
<td width="81" align="left"><bean:write name="regediter" property="password"/></td>
<td width="76" align="left"><bean:write name="regediter" property="msn"/></td>
<td width="68" align="left"><bean:write name="regediter" property="qq"/></td>
这个是Action 处理请求代码:
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
int current = 0 ;
String id = request.getParameter("id");
List list ;
if(id==null){
list = HibernateDbConnection.getInstance().findById();
}else{
list = HibernateDbConnection.getInstance().findById(Integer.valueOf(id));
}
Regediter regediter = (Regediter)list;
request.setAttribute("list", regediter);
request.setAttribute("current", current);
return mapping.findForward("success");
这个是异常信息:
avax.servlet.ServletException: java.lang.ClassCastException: java.util.ArrayList cannot be cast to customs.zheng.Web.Regediter
我标记的红色字体是错误的关键,寻求解决办法