python如何把一个列表的索引，换成另外一个列表的对应元素呢？

Question

谢谢哦！

Answer 1

这个有4种情况，看看你要哪一种

# 获取列表a的元素在列表b中的索引
a=["a","b","c"]
b=["b","c","a"]
c=[b.index(x)+1 for x in a]
print(c)  # [3, 1, 2]

# 获取列表b的元素在列表a中的索引
a=["a","b","c"]
b=["b","c","a"]
c=[a.index(x)+1 for x in b]
print(c)  # [2, 3, 1]

# 用列表c中的值为索引获取列表a的元素进行重新排列
a=["a","b","c"]
c=[3, 1, 2]
b=[a[x-1] for x in c]
print(b) # ['c', 'a', 'b']

# 把列表a的元素移动到列表c中的值为索引的位置
a=["a","b","c"]
c=[3, 1, 2]
b=[None] * len(a)
for v,i in zip(a,c):
    b[i-1] = v
print(b) # ['b', 'c', 'a']