C语言，指针方面的初级问题。新手求指导？

Question

#include<stdio.h>
void copy1(double target1[], double source[], int n);
void copy2(double * target2, double * source, int n);
void copy3(double * target3, double * source, double*sourceend);
int main(void)
{
    double source[5] = { 1.1,2.2,3.3,4.4,5.5 };
    double target1[5];
    double target2[5];
    double target3[5];

    copy1(target1, source, 5);
    copy2(target2, source, 5);
    copy3(target3, source, source+5);
    
    return 0;
}
void copy1(double target1[], double source[], int n)
{
    int i;
    for (i = 0; i < n; i++)
        source[i] = target1[i];
    printf("%d", target1[i]);
    printf("\n");
}
void copy1(double * target2, double *source, int n)
{
    int i;
    for (i = 0; i < n; i++)
        *source = *target2;
        source++;
        target2++;
    printf("%d", (*target2)++);
    printf("\n");
}
void copy3(double * target3, double * source, double*sourceend)
{
    double *i;
    for (i = source; i < sourceend; i++)
        *target3 += *i;
    printf("%d", (*target3)++);
    printf("\n");
}

这道题的要求是把source数组copy到target1，2，3的3个数组中。前提是以3种不同方式。可是我写好后，不能运行。看来看去也找不到错误的地方。奇怪，哪里有问题呢？

Answer 1

错的离谱。好多基本语法都没掌握，而且还粗心，函数名字都写错，都运行不起来。建议有时间看下谭浩强的《C程序设计  》,虽然不是很被认可，但简单易懂，作为基础学习足够了。

void copy1(double target1[], double source[], int n);
void copy2(double * target2, double * source, int n);
void copy3(double * target3, double * source, double*sourceend);

void copy1(double target1[], double source[], int n)
{
	int i;
	for (i = 0; i < n; i++){
		target1[i] = source[i];
		printf("%f\n", target1[i]);
		
	}
	printf("\n");
}
void copy2(double * target2, double *source, int n)
{
	int i;
	for (i = 0; i < n; i++){
		*target2 = *source;
		source++;
		printf("%f\n", *target2++);
		
	}
	printf("\n");
}
void copy3(double * target3, double * source, double*sourceend)
{
	double *i;
	for (i = source; i < sourceend; i++){
		*target3 = *i;
		printf("%f\n", *target3++);

	}
	printf("\n");
}