python 判断文本可读性等级

Question

Answer 1

参考代码：

def readability(text):
    import string
    cnum=0
    snum=0
    wnum = len(text.split(' '))
    for c in text:
        if c in string.punctuation or c==' ': 
            if c in ['.','!',',','...','?']:
                snum+=1 
            continue
        cnum+=1
    l=100*cnum/wnum
    s=100*snum/wnum
    clindex=round(0.058*l-0.296*s-15.8)
    print(clindex)
readability("Congratulations! Today is your day. You're off to Great Places! You're off and away!")