Python在多个字典中判断key是否相同，若相同就把value值相加

Question

求解：

一个txt文档中存了10个字典，每个字典里都有多个键值对，现在我想对10个字典中重复的键进行处理，把这个键对应的所有值加和当作他的新值，处理完毕后将所有字典中的键值对重新整合成一个字典，并按值的大小，由高到低排序输出，求Python实现代码~感谢！

Answer 1

准备数据花的时间多余写代码时间。

d1 = {
  "key11": 1,
  "key1": 11,
  "key2": 12,
  "key3": 13
}

d2 = {
  "key21": 2,
  "key1": 21,
  "key2": 22,
  "key3": 23
}

d3 = {
  "key31": 3,
  "key1": 31,
  "key2": 32,
  "key3": 33
}

d4 = {
  "key41": 4,
  "key1": 41,
  "key2": 42,
  "key3": 43
}
d5 = {
  "key51": 5,
  "key1": 51,
  "key2": 52,
  "key3": 53
}

d6 = {
  "key61": 6,
  "key1": 61,
  "key2": 62,
  "key3": 63
}

d7 = {
  "key71": 7,
  "key1": 71,
  "key2": 72,
  "key3": 73
}

d8 = {
  "key81": 8,
  "key1": 81,
  "key2": 82,
  "key3": 83
}

d9 = {
  "key91": 9,
  "key1": 91,
  "key2": 92,
  "key3": 93
}

d10 = {
  "key101": 10,
  "key1": 101,
  "key2": 102,
  "key3": 103
}

ds = [d1, d2, d3, d4, d5, d6, d7, d8, d9, d10]

m = dict()

for d in ds:
    for k, v in d.items():
        if k in m.keys():
            m[k] = m[k] + v
        else:
            m[k] = v

l = [(v, k) for k, v in m.items()]
l.sort(reverse = True)

for (v, k) in l:
    print(f'{k}: {v}')


// Output 
key3: 580
key2: 570
key1: 560
key101: 10
key91: 9
key81: 8
key71: 7
key61: 6
key51: 5
key41: 4
key31: 3
key21: 2
key11: 1

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