数据库中遍历 问题。。。。。。。。。。

Question

[code="java"]
public List> findMovieByRegion(String region){

    List<Map<String, Object>> movieList = new ArrayList<Map<String, Object>>();
    SQLiteDatabase db = dbHelper.getReadableDatabase();
    Cursor cursor = db.rawQuery("select num from Online_movie where region=?", new String[]{region});
    while(cursor.moveToNext()){

        int aa = cursor.getInt(cursor.getColumnIndex("num"));
        HashMap<String, Object> map = new HashMap<String, Object>();
        map.put("aaa", aa);
        System.out.println(map);
        movieList.add(map);
    }
    return movieList;
}

//______________________________________________
下面是 遍历上面 数据库中的 集合
MovieService ms = new MovieService(this.getBaseContext());

    List<Map<String,Object>> typenum =  ms.findMovieByRegion("美国");

    for (Iterator<Map<String, Object>> typeiterator = typenum.iterator(); typeiterator.hasNext();) {

        Object num = typeiterator.next();

//这里打印的 num 是{aaa=10},{aaa=9},{aaa=3}可是 我只想得到 10,9,3这几个数字 因为 有花括号的话 组成的路径就是错误的

Log.v("num===ggggggggggggggg>", ""+num);

        listmap = FileList.findFile(Environment.getExternalStorageDirectory()+"/Pictures/"+num+".jpg");

    }

[/code]

Answer 1

Object num = typeiterator.next(); 为什么用object接收，不用map呢。用map取得get(key)就可以了