根据商铺shopId查询用户tb_users得到多个用户的u_id来查询其它结果 <select id="selectStudentsStatisticalVoList" parameterType="integer" >/*parameterType="com.ruoyi.goods.entity.vo.StudentsStatisticalVo"*/ select tus.user_name, tus.user_avatar, td.name, (select count(*) from tb_study_goods where tus.shop_id = sg.shop_id and tus.u_id = sg.u_id) as studyFor, /*count(case when is_complete = 1 then 1 else null end ) as finishNum,*/ (select count(*) from tb_study_goods where tus.shop_id = sg.shop_id and tus.u_id = sg.u_id and sg.is_complete = 1) as finishNum, (select sum (study_length) from tb_study_goods where tus.shop_id = sg.shop_id and tus.u_id = sg.u_id) as studyLength, (select count (*) from tb_chapter_goods_rela where tcgr.shop_id = tus.shop_id and tcgr.train_id = #{trainId}) as course, (select create_time from tb_study_goods where tus.shop_id = sg.shop_id and tus.u_id = sg.u_id order by create_time) as createTime from tb_users tus left join tb_study_goods sg on tus.shop_id = sg.shop_id and tus.u_id = sg.u_id left join tb_chapter_goods_rela tcgr on tcgr.shop_id = tus.shop_id and tcgr.train_id = #{trainId} left join tb_department td on td.department_id = tus.depart_id where tus.shop_id = #{shopId} </select>
子查询返回值不止一个如何处理
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2条回答 默认 最新
- CSDN专家-sinJack 2021-06-03 19:23关注
加limit 1吧,就只返回一条了。
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