C语言 综 合 练 习 题

Question

续modi3.c

Answer 1

modi1.c
1. n
2. i
3. a[n-1-i]

modi2.c
for(i=2; i<=m; i++)
y -= 1/(i*i*1.0);

prog2.c
void fun(int a, int b, long *c){
    c += (a/10)*1000;
    c += (b/10)*100;
    c += (a%10)*10;
    c += (b%10);
    return;
}


blank3.c
1. n
2. else
3. a, b

modi3.c
k = i;
b = k%10;

prog3.c
void fun(char *ss){
    for(int i=0; i<strlen(ss); i++){
        if((i&2) && (ss[i]<='z') && (ss[i]>='a')){
            ss[i] = ss[i-32];
        }
    }
        return;
}