将YYYY/MM/DD形式的生日转化为英文日期形式。 要流程图，下面是代码，流程图怎么画。

Question

#include"stdio.h"
int f(int a,int b,int c)
{
if (
(c<=28&&c>=1) ||
((c<=31&&c>=1) &&
(b==1||b==3||b==5||b==7||b==8||b==10||b==12)) ||
((c<=30&&c>=1) &&
(b==4||b==6||b==9||b==11)) ||
((c<=29&&c>=1) &&
(b==2)&&(a%400==0||(a%4==0&&a%100!=0)))
)
return 0;
else
return 1;
}
int main()
{
int a,b,c;
scanf("%d/%d/%d",&a,&b,&c);

char *str[]={" ","January","February","March","April","May","June","July","August","September","October","November","December"};


printf("%s %d,%d\n%d",str[b],c,a);
return 0;

}

Answer 1

流程图就是: 输入年月日3个值 ---》创建一个字符串的数组 ----》以月份为下标从字符串数组中取得对应的月份英文 ---》按照 月份英文 日，年的格式输出