class testMedium200: #dfs deep-first search 树分支深度优先搜索
def dfs(self, grid, r, c):
grid[r][c] = 0
nr, nc = len(grid), len(grid[0])
for x, y in [(r-1,c),(r+1, c), (r, c-1), (r, c+1)]:
if 0 <= x < nr and 0 <= y <nc and grid[x][y] == '1':
self.dfs(grid, x, y)
def numIslands(self, grid): #grid: List[List(str)] #集合字符串最后以集合的方式接受输出打印
nr = len(grid)
if nr == 0:
return 0
nc = len(grid[0])
num_islands = 0
for r in range(nr):
for c in range(nc):
if grid[r][c] == '1':
num_islands += 1
self.dfs(grid, r , c)
return num_islands
grid = [ ["1","1","1","1","0"], ["1","1","0","1","0"],["1","1","0","0","0"],["0","0","0","0","0"
if __name__ == '__main__':
t = testMedium200()
target = 9
print(t.dfs(grid))
leetcode200题 dfs怎么打印呀,不会打印
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关注 有帮助的话,希望能够采纳支持一下,谢谢!
""" -*- coding:utf-8 -*- Author:yang-roc QQ:327844461 Email:aida_pc@qq.com Time: 2021-07-30 """ class testMedium200: # dfs deep-first search 树分支深度优先搜索 def dfs(self, grid, r, c): grid[r][c] = 0 nr, nc = len(grid), len(grid[0]) for x, y in [(r - 1, c), (r + 1, c), (r, c - 1), (r, c + 1)]: if 0 <= x < nr and 0 <= y < nc and grid[x][y] == '1': self.dfs(grid, x, y) def numIslands(self, grid): # grid: List[List(str)] #集合字符串最后以集合的方式接受输出打印 nr = len(grid) if nr == 0: return 0 nc = len(grid[0]) num_islands = 0 for r in range(nr): for c in range(nc): if grid[r][c] == '1': num_islands += 1 self.dfs(grid, r, c) return num_islands if __name__ == '__main__': t = testMedium200() # 示例① grid1 = [ ["1", "1", "1", "1", "0"], ["1", "1", "0", "1", "0"], ["1", "1", "0", "0", "0"], ["0", "0", "0", "0", "0"] ] print(t.numIslands(grid1)) # 示例② grid2 = [ ["1", "1", "0", "0", "0"], ["1", "1", "0", "0", "0"], ["0", "0", "1", "0", "0"], ["0", "0", "0", "1", "1"] ] print(t.numIslands(grid2))
程序运行截图:
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