SG978 2021-09-29 17:20 采纳率: 100%
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一套sql题有人会的吗?

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  • 神仙别闹 2021-09-29 17:39
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    此代码适用于MS SQL Server

    SELECT
    d.dept_id AS '部门编号',
    d.dept_name AS '部门名称',
    (SELECT COUNT(*) FROM employee WHERE  dept_id=d.dept_id AND emp_wage BETWEEN 0 AND 4999) AS '5K以下员工人数',
    (SELECT SUM(emp_wage) FROM employee WHERE  dept_id=d.dept_id AND BETWEEN 0 AND 4999) AS '5K以下薪酬小计',
    (SELECT COUNT(*) FROM employee WHERE  dept_id=d.dept_id AND emp_wage BETWEEN 5000 AND 10000) AS '5K-10K员工人数',
    (SELECT SUM(emp_wage) FROM employee WHERE  dept_id=d.dept_id AND emp_wage BETWEEN 5000 AND 10000) AS '5K-10K薪酬小计',
    (SELECT COUNT(*) FROM employee WHERE  dept_id=d.dept_id AND emp_wage>10000) AS '10K以上员工人数',
    (SELECT SUM(emp_wage) FROM employee WHERE  dept_id=d.dept_id AND emp_wage >10000) AS '10K以上薪酬小计',
    (SELECT COUNT(*) FROM employee WHERE  dept_id=d.dept_id) AS '部门员工人数总数',
    (SELECT SUM(emp_wage) FROM employee WHERE  dept_id=d.dept_id) AS '部门薪酬合计',
    (SELECT AVG(emp_wage) FROM employee WHERE  dept_id=d.dept_id) AS '部门薪酬均值',
    (SELECT MAX(emp_wage) FROM employee WHERE  dept_id=d.dept_id) AS '部门薪酬最大值',
    (SELECT MIN(emp_wage) FROM employee WHERE  dept_id=d.dept_id) AS '部门薪酬最小值'
    FROM department AS d ORDER BY d.dept_id ASC
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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  • 系统已结题 4月7日
  • 已采纳回答 3月30日
  • 创建了问题 9月29日

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