用lambda函数分别对字典value求和

Question

只要对每个字典求总和就行，字典如下：

dict1={
    'zhangsan':30,
    'lisi':40,
    'wangwu':90
}
dict2={
    'zhangsan':'30',
    'lisi':'40',
    'wangwu':'90'
}
dict3={
    'yiban':{
        'zhangsan':30,
        'zhangsi':40,
    },
    'erban':{
        'lisan':40,
        'lisi':50
    }
}

Answer 1

dict1={
    'zhangsan':30,
    'lisi':40,
    'wangwu':90
}
dict2={
    'zhangsan':'30',
    'lisi':'40',
    'wangwu':'90'
}
dict3={
    'yiban':{
        'zhangsan':30,
        'zhangsi':40,
    },
    'erban':{
        'lisan':40,
        'lisi':50
    }
}

s1 = (lambda x :sum(x.values()))(dict1)
s2 = (lambda x:sum([int(i) for i in x.values()]))(dict2)
s3 = (lambda x,y:sum(x.values()) + sum(y.values()))(*dict3.values())
print("s1 = {}".format(s1))
print("s2 = {}".format(s2))
print("s3 = {}".format(s3))