C语言编程问题求解答

Question

Answer 1

#include <stdio.h>
#include <stdlib.h> //system("pause")

main()
{
    int year, month, day, total, leap; //total总天数 ,leap用于闰年的2月天数
    scanf("%d%d%d", &year, &month, &day);
    if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) //判断是否闰年，闰年2月多一天，所以闰年leap为1，平年为leap为0。
    {
        leap = 1;
    }
    else
    {
        leap = 0;
    }

    switch (month) //根据月份计算对应的最终天数。
    {
    case 1:
        total = day;
        break;
    case 2:
        total = 31 * 1 + day;
        break;
    case 3:
        total = 31 * 1 + 28 + leap + day;
        break;
    case 4:
        total = 31 * 2 + 28 + leap + day;
        break;
    case 5:
        total = 31 * 2 + 28 + leap + 30 * 1 + day;
        break;
    case 6:
        total = 31 * 3 + 28 + leap + 30 * 1 + day;
        break;
    case 7:
        total = 31 * 3 + 28 + leap + 30 * 2 + day;
        break;
    case 8:
        total = 31 * 4 + 28 + leap + 30 * 2 + day;
        break;
    case 9:
        total = 31 * 5 + 28 + leap + 30 * 2 + day;
        break;
    case 10:
        total = 31 * 5 + 28 + leap + 30 * 3 + day;
        break;
    case 11:
        total = 31 * 6 + 28 + leap + 30 * 3 + day;
        break;
    case 12:
        total = 31 * 6 + 28 + leap + 30 * 4 + day;
        break; //12月之前的11个月中有6个31天，4个30天，2月为28天+leap。
    }

    if (year >= 1 && year <= 9999 && month >= 1 && month <= 12 && day >= 1 && day <= 31) //判断输入是否正解，年份最大为9999，可自行更改。
    {
        printf("%d\n",total);
    }
    else
    {
        printf("\n\t错误\n\n");
    }
    return 0;
}