这个 js 函数 可以用，但写的很low，很那个，哪位帮弄弄，

Question

data 数据格式：
所有对象，都有id:' ',  和 children:[ ],
对象中的，children 可能会嵌套 一个或多个对象，也可能是空[] ，而且嵌套很多层
现在我要 找出 id 为 ** 的对象，把它删除  
 如： {id: 1,children:[ {id: 2,children:[ {id: 3,children:[ {id: 4,children:[] }] }] }, {id: 5,children:[] }, {id: 6,children:[] }] }


export function deleteEl(data,id){
  // if(typeof data === 'undefined'){return data}
  // if(typeof data.children === 'undefined'){return data}
  if (data.children.length>=1){
    for(let i=0;i<data.children.length;i++){
      if(data.children[i].id=== id){
        data.children.splice(i,1)
        console.log('删除',id)
        return data
      }
      if(data.children[i].children.length >= 1) {
        for(let j=0; j < data.children[i].children.length; j++){
          if(data.children[i].children[j].id === id){
            data.children[i].children.splice(j,1)
            console.log('删除',id)
            return data
          }
          if(data.children[i].children[j].children.length>=1){
            for(let x=0; x< data.children[i].children[j].children.length; x++){
              if(data.children[i].children[j].children[x].id === id ){
                data.children[i].children[j].children.splice(x,1)
                console.log('删除',id)
                return data
              }
              if(data.children[i].children[j].children[x].children.length>=1){
                for(let y=0; y<data.children[i].children[j].children[x].children.length;y++){
                  if(data.children[i].children[j].children[x].children[y].id=== id){
                    data.children[i].children[j].children[x].children.splice(y,1)
                    console.log('删除',id)
                    return data
                  }
                  if(data.children[i].children[j].children[x].children[y].children.length>=1){
                    for(let z=0;z<data.children[i].children[j].children[x].children[y].children.length;z++){
                      if(data.children[i].children[j].children[x].children[y].children[z].id === id){
                        data.children[i].children[j].children[x].children[y].children.splice(z,1)
                        console.log('删除',id)
                        return data
                      }
                    }
                  }
                }
              }
            }
          }
        }
      }
    }
  }
}

Answer 1

递归删除下就行

    function deleteEl(children, id) {
        if (children.length)
            for (var i = 0; i < children.length; i++) {
                if (children[i].id == id) {
                    children.splice(i, 1);
                    return true;
                }
                deleteEl(children[i].children,id);
            }
    }
    var data = { id: 1, children: [{ id: 2, children: [{ id: 3, children: [{ id: 4, children: [] }] }] }, { id: 5, children: [] }, { id: 6, children: [] }] };

    deleteEl(data.children, 3);
    console.log(JSON.stringify(data, null, 2))
    console.log('----------------------')
    deleteEl(data.children, 5);
    console.log(JSON.stringify(data, null, 2))