C语言 利用洗牌将字符串随机打乱10次

Question

问题遇到的现象和发生背景

如果需要将下面的代码给改成，用户自己输入字符串，并且字符数不能少于5个，否则输出“String length must at least be 5. Please try again.”当输入长度为5或者以上的字符串时，将字符串洗牌shuffle10次

问题相关代码，请勿粘贴截图

#include <stdio.h>

void shuffle(int array[], int size) {
    for(int i = 0; i < size; i++) {
        int j = rand()%size;
        int t = array[i];
        array[i] = array[j];
        array[j] = t;
    }
}

int main(void){
    int list[10] = {0,1,2,3,4,5,6,7,8,9};

    shuffle(list, 10);
    for (int i = 0; i < 10; i++) {
        printf("%d,", list[i]);
    }
    return 0;
}

我想要达到的结果

Enter a string of length 5:
abc
String length must at least be 5. Please try again.
Enter a string of length 5:
abcde
Shuffle 1: adcbe
Shuffle 2: cdabe
Shuffle 3: bdace
Shuffle 4: badce
Shuffle 5: bedca
Shuffle 6: bedca
Shuffle 7: aedcb
Shuffle 8: acdeb
Shuffle 9: cadeb
Shuffle 10: cdaeb

Answer 1

加srand
并且字符串数不能少于5个---是字符数不少于5个吧？

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
void shuffle(char *s,int n) {
    int i,j;
    char t;
    for(i = 0; i < 10; i++) {
        j = rand()%n;
        t = s[i%n];
        s[i%n] = s[j];
        s[j] = t;
        printf("Shuffle %d: %s\n",i+1,s);
    }
}
int main(void){
    char s[100];
    printf("Enter a string of length 5:\n");
    gets(s);
    while(strlen(s) < 5)
    {
        printf("String length must at least be 5. Please try again.\n");
        printf("Enter a string of length 5:\n");
        gets(s);
    }
    srand(time(NULL));
    shuffle(s, strlen(s));
    return 0;
}