对输入矩形计算面积，该补充什么呀…

Question

｛#include
using namespace std;

struct Rect{
int width;
int height;
int area;
Rect *next;
};

Rect *head;

Rect* getNode();

void Create(){
if((head=getNode())==NULL)
return;
for(Rect *pE=head, *pS; pS=getNode(); pE=pS)
pE->next=pS;
}

int main()
{
Rect *temp;
Create();
if(head==NULL)
return -1;

for(Rect* p=head; p;)
{
    cout<<p->width*p->height<<endl;
    temp=p;
    p=p->next;
    delete temp;
}

return 0;

}// 在此处补充你的代码
｝

Answer 1

供参考：

#include <iostream>
using namespace std;
struct Rect{
    int width;
    int height;
    int area;
    Rect *next;
};

Rect* head;
Rect* getNode();
void Create()
{
    if((head=getNode())==NULL)
       return;
    for(Rect *pE=head, *pS; pS=getNode(); pE=pS)
       pE->next=pS;
}

int main()
{
    Rect *temp;
    Create();
    if(head==NULL)
       return -1;

    for(Rect* p=head; p;)
    {
       cout<<p->width*p->height<<endl;
       temp=p;
       p=p->next;
       delete temp;
    }
    return 0;
}
// 在此处补充你的代码
Rect* getNode()
{
    Rect *p = new Rect;
    if(!p)  return NULL;
    p->next = NULL;
    cin>>p->width>>p->height;
    p->area = p->width*p->height;
    if(p->width == 0 && p->height == 0){ //输入 0 0 时，结束输入。
       delete p;
       p = NULL;
    }
    return p;
}