java中想判断三角形是否成立，但不成功。

Question

import java.util.;
public class Triangle {
double x,y,z,p;
public double getX(){
return this.x;
}
public void steX(double x){
this.x=x;
}
public double getY(){
return this.y;
}
public void steY(double y){
this.y=y;
}
public double getZ(){
return this.z;
}
public void steZ(double z){
this.z=z;
}
public Triangle(double x,double y,double z){
this.x=x;
this.y=y;
this.z=z;
}
public double getPerimeter(){return p=x+y+z;}
public double getArea(){return (p/2)((p/2)-x)((p/2)-y)((p/2)-z);}
public static void main(String[] args){
Scanner sc=new Scanner(System.in);
double x=sc.nextDouble();
double y=sc.nextDouble();
double z=sc.nextDouble();
sc.close();
if((x+y)<z&&(x+z)<y&&(z+y)<x){
System.out.println("三角形不存在");
}
else{
Triangle a=new Triangle(x,y,z);
double b=a.getPerimeter();
double c=a.getArea();
System.out.println("三角形的周长"+b);
System.out.println("三角形的面积"+Math.sqrt(c));}
}
}

Answer 1

这里判断应该用或

任意两边之和大于第三边可以构成三角形，对立面是有一组两边之和小于等于第三边就不符合

if((x+y)<=z||(x+z)<=y||(z+y)<=x)

import java.util.Scanner;
 public class Triangle {
double x,y,z,p;
public double getX(){
return this.x;
}
public void steX(double x){
this.x=x;
}
public double getY(){
return this.y;
}
public void steY(double y){
this.y=y;
}
public double getZ(){
return this.z;
}
public void steZ(double z){
this.z=z;
}
public Triangle(double x,double y,double z){
this.x=x;
this.y=y;
this.z=z;
}
public double getPerimeter(){return p=x+y+z;}
public double getArea(){
    return (p/2)*((p/2)-x)*((p/2)-y)*((p/2)-z);}
public static void main(String[] args){
Scanner sc=new Scanner(System.in);
double x=sc.nextDouble();
double y=sc.nextDouble();
double z=sc.nextDouble();
sc.close();
if((x+y)<=z||(x+z)<=y||(z+y)<=x){
System.out.println("三角形不存在");
}
else{
Triangle a=new Triangle(x,y,z);
double b=a.getPerimeter();
double c=a.getArea();
System.out.println("三角形的周长"+b);
System.out.println("三角形的面积"+Math.sqrt(c));}
}
}