请问怎样才能让a in b得出True

Question

s=""
a=['1','2']
for i in a:
    s+=i
b=['1','2','3']
a in b

具体题目在下方

def cookable_recipes(ings, recipes):
    """
    >>> rec = {'Egg Fried Rice': ['egg', 'rice', 'msg'], \
'Spaghetti': ['noodle', 'tomato sauce'], 'Steamed Rice': ['rice']}
    >>> cookable_recipes(['egg', 'msg', 'rice'], rec)
    ['Egg Fried Rice', 'Steamed Rice']
    >>> cookable_recipes(['egg', 'rice', 'msg', 'noodle', 'tomato sauce'], rec)
    ['Egg Fried Rice', 'Spaghetti', 'Steamed Rice']
    >>> cookable_recipes(['egg'], rec)
    []

    """
    keys = [i for i in recipes] 
    values=list(recipes.values())
    result=[]
    for i in values:
        if i in ings:
            result.append(i)
    return result

Answer 1

 
s=""
a=['1','2']
for i in a:
    s+=i
b=['2','3','1']
a in b

这样 a in b 是True 吗？

如果是True ， 那就遍历a，判断a的元素都在b 里就返回True