小小白每天不奋斗 2022-05-09 16:36 采纳率: 80%
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已结题

如何根据属性值重组数组(语言-javascript)

原数组:

    arr[5] = [
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202211"},
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202212"},
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202210"},
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202210"},
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202211"}
]

期望得到的数组:

```javascript
arr1= [
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202211"},
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202211"}
]
arr2 = [
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202210"},
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202210"},
]
arr3 = [{
{FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "",FeeMon: "202212"},
}]

arr4 = [arr1,arr2,arr3]

```}]

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2条回答 默认 最新

  • Heerey525 前端领域新星创作者 2022-05-09 17:21
    关注
    
    let arr = [
        { FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "", FeeMon: "202211" },
        { FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "", FeeMon: "202212" },
        { FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "", FeeMon: "202210" },
        { FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "", FeeMon: "202210" },
        { FeeID: "00032", ItemName: "XXXXXX", ItemTypeName: "物业费", InstallSite: "", EndNum: "", FeeMon: "202211" }
    ]
    
    const getArray = (arr) => {
        let map = new Map()
        for (let item of arr) {
            const temp = item.FeeMon
            if (!map.has(temp)) {
                map.set(temp, [item])
            } else {
                console.log('map.get(temp)', map.get(temp))
                map.set(temp, [...map.get(temp), item])
            }
        }
        return [...map.values()]
    }
    
    console.log('getArrayMax', getArray(arr))
    
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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  • 系统已结题 5月18日
  • 已采纳回答 5月10日
  • 创建了问题 5月9日

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