求C语言汉诺塔可视化代码

Question

我在网上找到的编译出来是cpp的，求帮我弄一个.c的，我改了俩天实在不会了

Answer 1

/*------------------------------------
project ： 汉诺塔演示软件；
language：     C语言
author：   404name
叠64层需要开全窗口并且将字号调整为6
------------------------------------0-*/

#include <stdio.h>
#include <windows.h>
int len, width, left, mid, right, time;

char map[80][1000];

int next[4][2] = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}}; //上0下1左2右3；

int turn[2][3] = {{0, 3, 1},  //a -> b   b -> c a -> c  上右下
                  {0, 2, 1}}; //b -> a  c -> b  c -> a    上左下
void gotoxy(int x, int y)
{
    HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
    COORD pos;
    pos.X = x;
    pos.Y = y;
    SetConsoleCursorPosition(handle, pos);
}

int init()
{
    system("color 30");
    printf("请输入你要递归的\n汉诺塔数目_");
    int n;
    scanf("%d", &n);
    time = 50 / n;
    left = 1, mid = 2 * (n + 1), right = mid + 2 * n + 1;
    len = 3 * (2 * n + 1);
    width = n + 1;
    for (int i = 0; i <= width; i++)
    {
        for (int j = 0, num = i; j <= len; j++)
        {
            if (i == 0 || j == 0 || i == width || j == len)
                map[i][j] = '#';
            if ((i > 1 && i < width) && (j == mid - 1 || j == right - 1))
                map[i][j] = '|';
            if (num && (i >= 1 && i <= width - 1) && j % 2 != 0 && j < mid)
            {
                map[i][j] = -95;
                map[i][j + 1] = -10; //打印 ■  ■占2个字节可以拆开来
                num--;
            }
        }
    }
    gotoxy(0, 0); //容易出现东西卡顿
    for (int i = 0; i <= width; i++)
    {
        for (int j = 0; j <= len; j++)
            printf("%c", map[i][j]);
        printf("\n");
    }
    return n;
}

void play(int x, int y)
{
    int turn_0, n = 0, i, j, k, tx, ty, flag = 0;
    if ((x == mid && y == right) || (x == left && y == mid) || (x == left && y == right))
        turn_0 = 0; //往右
    else if ((x == mid && y == left) || (x == right && y == left) || (x == right && y == mid))
        turn_0 = 1; //往左
    for (i = 1, j = y; i <= width; i++)
    { //目的地
        if (map[i][j] != 0)
        {
            tx = i - 1;
            ty = j;
            break;
        }
    }
    for (i = 1, j = x; i <= width; i++)
    { //出发点
        if (map[i][j] != 0)
        {
            break;
        }
    }
    while (1)
    {
        while ((i != 1 || j != x) && (i != 1 || j != y) && (i != tx || j != ty))
        {
            if (turn_0 == 0)
                for (k = mid - 3; k >= 0; k--)
                {
                    map[i + next[turn[turn_0][n]][0]][j + next[turn[turn_0][n]][1] + k] = map[i][j + k];
                    map[i][j + k] = 0;
                }
            else
                for (k = 0; k < mid - 2; k++)
                {
                    map[i + next[turn[turn_0][n]][0]][j + next[turn[turn_0][n]][1] + k] = map[i][j + k];
                    map[i][j + k] = 0;
                }
            gotoxy(j, i);
            Sleep(time);
            for (k = 0; k < mid - 2; k++)
            {
                printf(" ");
            }
            i = i + next[turn[turn_0][n]][0];
            j = j + next[turn[turn_0][n]][1];
            gotoxy(j, i);
            Sleep(time);
            for (k = 0; k < mid - 2; k++)
            {
                printf("%c", map[i][j + k]);
            }
        }
        n++; //改变方向;
        if (i == tx && j == ty)
            return;
        if (turn_0 == 0)
            for (k = mid - 3; k >= 0; k--)
            {
                map[i + next[turn[turn_0][n]][0]][j + next[turn[turn_0][n]][1] + k] = map[i][j + k];
                map[i][j + k] = 0;
            }
        else
            for (k = 0; k < mid - 2; k++)
            {
                map[i + next[turn[turn_0][n]][0]][j + next[turn[turn_0][n]][1] + k] = map[i][j + k];
                map[i][j + k] = 0;
            }
        gotoxy(j, i);
        for (k = 0; k < mid - 2; k++)
        {
            printf(" ");
        }
        Sleep(time);
        i = i + next[turn[turn_0][n]][0];
        j = j + next[turn[turn_0][n]][1];
        gotoxy(j, i);
        for (k = 0; k < mid - 2; k++)
            printf("%c", map[i][j + k]);
        Sleep(time);
    }
}

void move(int a, int b, int c, char aa, char bb, char cc, int n)
{
    if (n == 1)
    {
        gotoxy(0, width + 1);
        printf("from %c to %c", aa, cc);
        play(a, c);
        return;
    }
    move(a, c, b, aa, cc, bb, n - 1);
    gotoxy(0, width + 1);
    printf("from %c to %c", aa, cc);
    play(a, c);
    move(b, a, c, bb, aa, cc, n - 1);
    gotoxy(0, width + 1);
}

int main()
{
    int n = init();
    move(left, mid, right, 'a', 'b', 'c', n);
    return 0;
}