while（$ row = mysqli_fetch_array（$ result））{当选择多个表时

Question

I'm creating this search function with PHP, javascript and mysql.

This code is working like it should. I type in some data in a a html search box, which sends the %keyword% to this PHP function, which returns the data as I want.

$query = "SELECT id,fornavn,efternavn,adresse,postnr,city,tlf,kon,email,fodselsdag FROM kunde WHERE email LIKE '%$keyword%' OR fornavn LIKE '%$keyword%'";


$result = mysqli_query($dbc,$query);

if($result){
    if(mysqli_affected_rows($dbc)!=0){
      while($row = mysqli_fetch_array($result,MYSQLI_ASSOC)){
        listings($row['fornavn'],$row['efternavn'], $row['email'],$row['adresse'],$row['tlf'],$row['postnr'],$row['city'],$row['fodselsdag'],$row['id'],$bartype);
    }

I have another TABLE where the id from the SQL above is stored in relation to another ID. The table looks like this:

Table name: vip
Colmns: id, brugerid, barid

Now I want to be customize the SQL in the code above, so it only picks data that also has a relation in the vip table.

I do it this way:

SELECT *, kunde.id as kundeid FROM kunde,vip WHERE  vip.brugerid = kunde.id AND vip.barid =1 AND email LIKE '%$keyword%' OR fornavn LIKE '%$keyword%';

Actually whenever I add more than one table, the php code stops working.. any idea why this is happening? And how I can achieve this?

Any help will be very appreciated

Answer 1

http://dev.mysql.com/doc/refman/5.0/en/join.html

SELECT *, kunde.id as kundeid FROM kunde INNER JOIN vip ON (vip.brugerid = kunde.id) WHERE  kunde.id=1 AND email LIKE '%$keyword%' OR fornavn LIKE '%$keyword%'