时间显示为像地址的乱码？

Question

#include<stdio.h>

struct time{
int hour;
int minutes;
int seconds;
};

struct time timeUpdate(struct time now);

struct time timeUpdate(struct time now)
{
++now.seconds;
if( now.seconds == 60){
now.seconds =0;
++now.minutes;

    if(now.minutes == 60){
        now.minutes = 0;
        ++now.hour;
        
        if(now.hour ==24){
            now.hour = 0;
        }
    }
}

};

int main(void)

struct time testTimes[5] = 
    {11,59,59},{12,0,0},{1,29,59},{23,59,59},{19,12,27}

int i;

for( i=0;i<5;++i)
    printf("Time is %.2i:%.2i:%.2i",
    testTimes[i].hour,testTimes[i].minutes,testTimes[i].seconds);
    
    testTimes[i] = timeUpdate(testTimes[i]);
    
    printf("...one second later it's %.2i:%.2i:%.2i\n",
    testTimes[i].hour,testTimes[i].minutes,testTimes[i].seconds);


return 0;

编译通过，但运行错误

Answer 1

问题很多：

1. timeUpdate 函数，你返回值没有
2. timeUpdate 函数最后大括号，后面不要加分号
3. timeUpdate 的参数最好用指针
4. timeUpdate 返回值不需要，直接将形参用指针带入