3.5 3.7初学c++ 怎么做啊 好难啊 帮帮我 不知道怎么办 好难啊 有没有
4条回答 默认 最新
- 来灵 2022-09-22 16:24关注
3.5代码如下
#include <iostream> using namespace std; int main() { int today, elapsed;//定义变量类型 cout << "Please enter an integer representing the day of the week today" << endl; cout << "For example,Monday is 1.In particular,Sunday is 0." << endl; cout << "Enter today's day : ";//今天周几 cin >> today; cout << "Enter the number of days elapsed since today : ";//距离今天有几天 cin >> elapsed; int day; day = (today + elapsed) % 7;//判断未来是周几 switch (today)//用分支语句判断今天周几 { case 0: cout << "Today is Sunday" << endl; break; case 1: cout << "Today is Monday" << endl; break; case 2: cout << "Today is Tuesday" << endl; break; case 3: cout << "Today is Wednesday" << endl; break; case 4: cout << "Today is Thursday" << endl; break; case 5: cout << "Today is Friday" << endl; break; case 6: cout << "Today is Saturday" << endl; break; } switch (day)//用分支语句判断未来周几 { case 0: cout << "The future day is Sunday" << endl; break; case 1: cout << "The future day is Monday" << endl; break; case 2: cout << "The future day is Tuesday" << endl; break; case 3: cout << "The future day is Wednesday" << endl; break; case 4: cout << "The future day is Thursday" << endl; break; case 5: cout << "The future day is Friday" << endl; break; case 6: cout << "The future day is Saturday" << endl; break; } system("pause"); return 0; }
运行结果如下图
3.7代码如下
#include<stdio.h> void swap(int* pt1, int* pt2) //交换指针指向值 { int temp; temp = *pt1; *pt1 = *pt2; *pt2 = temp; } void exchange(int* p1, int* p2, int* p3) { if (*p1 > *p2) //如果p1指针指向的数大于p2,则交换指针指向值 swap(p1, p2); if (*p1 > *p3) //同上 swap(p1, p3); if (*p2 > *p3) //同上 swap(p2, p3); } int main() { int a, b, c; //定义三个变量 int* p1, * p2, * p3; //定义三个指针 printf("请输入3个整数,整数之间用空格隔开: \n"); scanf("%d %d %d", &a, &b, &c); //输入三个数值 p1 = &a, p2 = &b, p3 = &c; //把a,b,c三个数的地址赋值给对应指针 exchange(p1, p2, p3); //调用函数 printf("%d,%d,%d\n", a, b, c); //将调换后的值顺序输出 int wait = 1; scanf("%d", &a); return 0; }
运行截图如下图
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