doutan3192 2019-02-24 10:08
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为什么Class扩展不会获得私有变量

The following code does not produce the output with the name Jock. I suspect because in the class Animal the $name is private, but the construct is public so should the subclass not be able to get the $name from the construct. I do not want to make $name public.

class Animal{
    private $name;
    public function __construct($name) {
        $this->name = $name;
    }
    public function Greet(){
        echo "Hello, I'm some sort of animal and my name is ", $this->name ;
    }
}

 class Dog extends Animal{
     private $type;

     public function __construct($name,$type) {
         $this->type = $type;
           parent::__construct($name);

     }
     public function Greet(){
         echo "Hello, I'm a ", $this->type, " and my name is ", $this->name;
     }
 }
   $dog2 = new Dog('Jock','dog');
   $dog2->Greet();
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3条回答 默认 最新

  • dtio35880438 2019-02-24 10:24
    关注

    the private variable only accessed inside the same class, you need to use protected for the name variable in class Animal.

    class Animal{
        protected  $name;
        public function __construct($name) {
            $this->name = $name;
        }
        public function Greet(){
         echo "Hello, I'm some sort of animal and my name is ", $this->name;
      }
    }
    class Dog extends Animal{
     private $type;
    
     public function __construct($name,$type) {
         $this->type = $type;
           parent::__construct($name);
    
     }
     public function Greet(){
         echo "Hello, I'm a ", $this->type, " and my name is ", $this->name;
      }
     }
    $dog2 = new Dog('Jock','dog');
    $dog2->Greet();
    
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