从不兼容的指针类型传递参数

Question

#include<stdio.h>

void mat_add(const int a[4][3],const int b[4][3],int c[4][3])

 int i,j;
 for(i=0;i<4;i++)
      for(j=0;j<4;j++)
         c[i][j] = a[i][j] + b[i][j]; 

void mat_print(const int m[4][3])

int i,j;
for (i=0;i<4;i++){
    for(j=0;j<4;j++)
        printf("%4d", m[i][j]);
   putchar('\n');

int main(void)

int tensu1[4][3] = { {91,63,78},{67,72,46},{89,34,53},{32,54,34} };
int tensu2[4][3] = { {97,67,72},{33,74,25},{49,56,38},{69,57,76} };
int sum[4][3];

mat_add(tensu1,tensu2,sum);

puts("第一次考试的分数");          mat_print(tensu1);
puts("第二次考试的分数");          mat_print(tensu1);
puts("总分");                      mat_print(sum);

return 0;

编译出的warning类似这样:
27 2 D:\dev\code\follow\list6-16.c [Warning] passing argument 1 of 'mat_add' from incompatible pointer type [enabled by default]
翻译出 [警告] 从不兼容的指针类型传递“mat_add”的参数 1 [默认启用]
要如何修改

Answer 1

把形参中const删了