PHP：动态获取扩展当前类的类的名称[复制]

Question

This question already has an answer here:

• How do I get class name in PHP? 10 answers

I have an abstract class and an extending class:

abstract class MyAbstract {
    public function getName(){echo static::class;}
}

class MyExtends extends MyAbstract {}

I would like to dynamically get the name of any extending class when getName() is called:

$c = new MyExtends();
echo $c->getName(); // expect: "MyExtends"

This works well on PHP 5.6+ (demo), but the project I'm working on is limited to PHP 5.3 and I have no leverage to change that. On that version, a parse error is thrown:

Parse error: syntax error, unexpected T_CLASS, expecting T_STRING or T_VARIABLE or '$'

So I modified the function to:

public function getName(){echo __CLASS__;}

Of course, this just echoes the parent name -- MyAbstract, so it doesn't work. Only thing I've thought of is to override getName() with a new implementation in each extending class, but that doesn't scale well: the whole point of inheritance is to concentrate common codebase in a parent (and of course the real function is not a one-liner).

Any idea how I can dynamically get the extending class name from the context of the abstract parent class in PHP 5.3?

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Answer 1

You can use get_class to get the name of class:

<?php
abstract class MyAbstract
{
    public function getName()
    {
        echo get_class($this);
    }
}

class MyExtends extends MyAbstract 
{
}

$c = new MyExtends();
echo $c->getName(); // expect: "MyExtends"

demo: https://ideone.com/TtMtZ7

The above code should work on all versions (since 5.0.4).