将PHP数组值与字符串的PART进行比较

Question

I'm trying to automate sifting through my online bank statements. Here's a trivial example of what I need.

I have an array of restaurants against which I sort my credit card statements:

$restaurants = array(
    array("vendor" => "default",
            "type" => "default"
    ),
    array("vendor" => "dunkin",
            "type" => "pastry"
    ),
    array("vendor" => "mcdonald",
            "type" => "fastfood"
    ),
    array("vendor" => "olive",
            "type" => "italian"
    )
);

The statement entries themselves can be a rather descriptive string:

$string = "McDonald's Restaurants Incorporated";

I've tried using array_search and in_array, but they seem to do the reverse of what I need, or they need an exact match like in the example below, but it is not what I need:

$result = array_search($string, array_column($restaurants, 'vendor'));
return $restaurants[$result]['type'];

// returns "default" because "McDonald's Restaurants Incorporated" != "mcdonald"

I would like to be able to match the array value "mcdonald" to any string that contains that chunk of it, and then return type "fastfood" for it. Don't worry about handling multiple occurrences.

Answer 1

You'll need a combination of things - a search-in-string method, and for it to be case insensitive.

You can accomplish this with something like this:

/**
 * Perform a string-in-string match case insensitively
 * @param  string $string
 * @param  array  $restaurants
 * @return string|false
 */
function findRoughly($string, $restaurants)
{
    $out = false;
    foreach ($restaurants as $restaurant) {
        // Set up the default value
        if ($restaurant['type'] == 'default' && !$out) {
            $out = $restaurant['type'];
            // Stop this repetition only
            continue;
        }
        // Look for a match
        if (stripos($string, $restaurant['vendor']) !== false) {
            $out = $restaurant['type'];
            // Match found, stop looking
            break;
        }
    }
    return $out;
}

And use it like so:

$result = findRoughly("McDonald's", $restaurants);

Example here.