PHP比较两个日期数组并检查匹配

Question

I want have two arrays with date objects which I want to compare. The first array contains todays date and the next five days:

$today = date('Y-m-d');
$fiveDays = [];
for($i=0; $i <= 5; $i++){
    $today = date('Y-m-d', strtotime('+1 day', strtotime($today)));
    $fiveDays[] = date('Y-m-d', strtotime($today));
}

which gives the result:

0: "2018-09-14"
1: "2018-09-15"
2: "2018-09-16"
3: "2018-09-17"
4: "2018-09-18"
5: "2018-09-19"

the other array can contain multiple objects:

[{
   days: (4) ["2018-09-13", "2018-09-14", "2018-09-15", "2018-09-16"]
   duration: 4
   end: "2018-09-16"
   name: "vacation blabla"
   start: "2018-09-13"
},
{
   days: (5) ["2018-09-20", "2018-09-21", "2018-09-22", "2018-09-23", "2018-09-24"]
   duration: 5
   end: "2018-09-24"
   name: "vacation blabla"
   start: "2018-09-20"
}]

Now I want to check if one of the days/dates of the first array will or is in the vacations_array. How can I achieve that?

EDIT

When a match is found, the second array(with the vacation-periods) where the match is true, must be assigned to a $vacation-array

Answer 1

You can do it this way too:

$result_array = array();
$found = false;
for($i=0; $i<count($vacation_array); $i++) {
  $found = false;
  for($j=0; $j<count($vacation_array[$i]['days']); $j++) {
    if(in_array($vacation_array[$i]['days'][$j], $array_1) && !$found) {
      $result_array[] = $vacation_array[$i];
      $found = true;
    }
  }
}
print_r($result_array);