douxue7196 2013-07-24 11:25
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如何生成每周报告?

i was able to generate a weekly report using some date function. The table looks like

-------------------------------------------------------------------------
week |Sunday  |Monday  |Tuesday |Wednesday |Thursday |Friday  |Saturday |
     |July 21 |July 22 |July 23 |July 24   |July 25  |July 26 |July 27  |
-------------------------------------------------------------------------

but whenever the current week consists of 2 months, like end of July and start of August. i am unable to find the current week. The table looks like

-------------------------------------------------------------------------
week |Sunday  |Monday  |Tuesday |Wednesday |Thursday |Friday  |Saturday |
     |July 28 |July 29 |July 30 |July 31   |July 32  |July 33 |July 34  |
-------------------------------------------------------------------------

please help. The result should look like

--------------------------------------------------------------------------
week |Sunday  |Monday  |Tuesday |Wednesday |Thursday |Friday   |Saturday |
     |July 28 |July 29 |July 30 |July 31   |August 1 |August 2 |August 3 |
--------------------------------------------------------------------------
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  • doushi7819 2013-07-24 11:30
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    I assume you have the first day of the week as a starting point?

    Then use phps stringtotime to easily progress in days:

    <?php
       $startOfWeek = date("Y-m-d", strtotime("Monday this week"));
    
       for ($i=0; $i<7;$i++){
           echo date("l, d M", strtotime($startOfWeek . " + $i day"))."<br />";
       }
    ?>
    

    Output:

    Monday, 29 Jul
    Tuesday, 30 Jul
    Wednesday, 31 Jul
    Thursday, 01 Aug
    Friday, 02 Aug
    Saturday, 03 Aug
    Sunday, 04 Aug
    

    format as required.

    Update to your Question:

    //find week start
    $weekstart = date("Y-m-d", strtotime("Monday this week"))   ;
    echo $weekstart; 
    

    strtotime is pretty flexible .

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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