dsa4d4789789 2015-07-13 19:57
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Array Unique执行后不显示某个数组

I'm using array_unique() to remove a duplicate value but it gives me an error when the value comes from a string then converted using explode, and values not displaying correctly

I'm using http://phptester.net/ to test

$email = 'general@t.com,info@t.com,info@t.com,jaa@t.com';

$emailList = array_unique(array_filter(array_map('trim',explode(',',$email))));

for($i = 0; $i < count($emailList); $i++){
    echo $emailList[$i];
}
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  • dqtiober37522 2015-07-13 20:08
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    I would do it like this :

    $email = 'general@t.com,info@t.com,info@t.com,jaa@t.com';
    
    $emailList = (array_map('trim',explode(',',$email)));
    
    $result = array_unique($emailList);
    var_dump($result);
    

    In case you want to print the array values, using for-loop, you can do like this:

    $email = 'general@t.com,info@t.com,info@t.com,jaa@t.com';
    
    $emailList = (array_map('trim',explode(',',$email)));
    
    $result = array_unique($emailList);
    
    for($i = 0; $i < count($emailList); $i++){
        if( $emailList[$i]!=null)
           echo $emailList[$i];
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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