doudg60800 2017-01-18 16:35
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用原始数据发送请求

I want to send a request with guzzle that looks like this.

Post man request

Thing is, I always get

Uncaught exception 'GuzzleHttp\Exception\ClientException' with message 'Client error: POST http://localhost:8080/project/user/login resulted in a 400 Bad Request

Here is the part of the code that creates and sends the request:

if (isset ($_REQUEST['username']) && isset($_REQUEST['password'])){
require '../php/vendor/autoload.php';

$myClient = new GuzzleHttp\Client();

$request = $myClient->post("http://localhost:8080/project/user/login");
$request->setBody($_REQUEST['username']. ',' . $_REQUEST['password']);
$feed_response = $request->send();

I've read most of the guzzle's manual, but it got me nowhere.

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  • doupinge9055 2017-01-19 05:04
    关注

    What version of Guzzle are you using. Use the latest version. In the latest version of Guzzle, a http POST request is sent as:

    $client->request('POST', '/post', [
        'form_params' => [
            'foo' => 'bar',
            'baz' => ['hi', 'there!']
        ]
    ]);
    

    See this link: http://docs.guzzlephp.org/en/latest/request-options.html?#form-params

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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