C语言 打印漏斗的实现：

Question

题目描述

打印出一个底部有n个*的漏斗

输入
第一行输入一个T；表示有T组测试数据
下面每一行都有一个n表示漏斗底部*的个数
n保证是奇数

输出
输出打印结果
两个测试答案之间要用换行分割

例子：
3
11
13
15

输出：

---

---

---

---

***
 *
***

---

---

---

---

---

---

---

---

*****
 ***
  *
 ***
*****

---

---

---

---

---

---

---

---

*******
 *****
  ***
   *
  ***
 *****
*******

---

---

---

---

Answer 1

int main()
{
    int T, n, i, j;
    scanf("%d", &T);
    while(T--)
    {
        scanf("%d", &n);
        for (j = n; j > 0; j -= 2)
        {
            for (i = 0; i < (n - j) / 2; i++)
                printf(" ");
            for (i = 0; i < j; i++)
                printf("*");
            printf("\n");
        }
        for (j = 3; j <= n; j += 2)
        {
            for (i = 0; i < (n - j) / 2; i++)
                printf(" ");
            for (i = 0; i < j; i++)
                printf("*");
            printf("\n");
        }
    }
    return 0;
}