drxnfdx798517235 2014-12-08 16:58
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如何使用phpWord和使用cloneBlock将变量复制到模板中

Using phpWord in my application, I try to clone a block in the template like this :

${CLONEME} <br>
     You may also notice that there’s one text break (empty paragraph) before this one that can be created also by PHPWord ${item}" <br>
${/CLONEME}

Doing this in my php code : $document->cloneBlock('CLONEME', 2}

I obtain :

" You may also notice that there’s one text break (empty paragraph) before this one that can be created also by PHPWord ${item}
You may also notice that there’s one text break (empty paragraph) before this one that can be created also by PHPWord ${item} "

but ${item} don't duplicate.

I want to have :

" You may also notice that there’s one text break (empty paragraph) before this one that can be created also by PHPWord ${item#1} You may also notice that there’s one text break (empty paragraph) before this one that can be created also by PHPWord ${item#2} "

How can I do this ? Thanks

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  • douaonong7807 2014-12-09 06:58
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    I see 2 possibilities:

    1. extend the cloneBlock method to do what you want (or write your own) - and have a look at the cloneRow method to see how they're doing the {item}->{item#1} replacement
    2. just live with multiple {item}-tags after cloneBlock and do several calls to setValue($search, $replace, 1), limiting the replacements to one at a time

    Hope that helps...

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