将CESU-8转换为高性能的UTF-8

Question

I have some raw text that is usually a valid UTF-8 string. However, every now and then it turns out that the input is in fact a CESU-8 string, instead. It is possible to technically detect this and convert to UTF-8 but as this happens rarely, I would rather not spend lots of CPU time to do this.

Is there any fast method to detect if a string is encoded with CESU-8 or UTF-8? I guess I could always blindly convert "UTF-8" to UTF-16LE and then to UTF-8 using iconv() and I would probably get the correct result every time because CESU-8 is close enough to UTF-8 for this to work. Can you suggest anything faster? (I'm expecting the input string to be CESU-8 instead of valid UTF-8 around 0.01-0.1% of all string occurrences.)

(CESU-8 is a non-standard string format which contains 16-bit surrogate pairs encoded in UTF-8. Technically UTF-8 strings should contain the characters represented by those surrogate pairs, not the surrogate pairs itself.)

Answer 1

Here's a more efficient version of your conversion function:

$regex = '@(\xED[\xA0-\xAF][\x80-\xBF]\xED[\xB0-\xBF][\x80-\xBF])@';
$s = preg_replace_callback($regex, function($m) {
    $in = unpack("C*", $m[0]);
    $in[2] += 1; // Effectively adds 0x10000 to the codepoint.
    return pack("C*",
        0xF0 | (($in[2] & 0x1C) >> 2),
        0x80 | (($in[2] & 0x03) << 4) | (($in[3] & 0x3C) >> 2),
        0x80 | (($in[3] & 0x03) << 4) | ($in[5] & 0x0F),
        $in[6]
    );
}, $s);

The code only converts high surrogates followed by low surrogates, and converts the two three-byte CESU-8 sequences directly into a four-byte UTF-8 sequence, i.e. from

ED       A0-AF    80-BF    ED       B0-BF    80-BF
11101101 1010aaaa 10bbbbbb 11101101 1011cccc 10dddddd

to

F0-F4    80-BF    80-BF    80-BF
11110oaa 10aabbbb 10bbcccc 10dddddd    // o is "overflow" bit

Here's an online example.