关于#c++#的问题：程序没法运行不知道怎么回事，求解答将员工信息按照职工号大小排序再在输出到磁盘文件中保存

Question

程序没法运行不知道怎么回事，求解答
将员工信息按照职工号大小排序再在输出到磁盘文件中保存。

#include<iostream>
#include<fstream>
using namespace std;
struct employee
{
    int num;//职工号
    string name;//姓名
    int age;//年龄
    int mon;//工资
};
int main()
{
    struct employee temp;
    struct employee emp[5] =
    {
        {002,"wang",56,3000},
        {001,"li",34,4000},
        {004,"zhu",23,5000},
        {003,"bao",24,6000},
        {050,"chao",19,3000}
    };//输入信息
    for (int i = 0; i <= 4; i++)
    {
        for (int j = 0; j <= 4 - i; j++)
        {
            if (emp[j].num >emp[j + 1].num)
            {
                emp[j] = temp;
                emp[j] = emp[j + 1];
                emp[j + 1] = temp;
            }
        }
    }
    //冒泡排序
    ofstream infile("职工表");
    for (int i = 0; i <= 4; i++)
    {
        infile << emp[i].num;
        infile << emp[i].name;
        infile << emp[i].age;
        infile << emp[i].mon;
    }
    infile.close();
    return 0;
}

Answer 1

改动处见注释，供参考:

#include<iostream>
#include<fstream>
using namespace std;
struct employee
{
    int num;//职工号
    string name;//姓名
    int age;//年龄
    int mon;//工资
};
int main()
{
    struct employee temp;
    struct employee emp[5] =
    {
        {2,"wang",56,3000},
        {1,"li",34,4000},
        {4,"zhu",23,5000},
        {3,"bao",24,6000},   //......
        {50, "chao",19,3000} //{050,"chao",19,3000}  修改
    };//输入信息
    for (int i = 0; i < 4; i++)  //(int i = 0; i <= 4; i++)  修改
    {
        for (int j = 0; j < 4 - i; j++)  // (int j = 0; j <= 4 - i; j++)  修改
        {
            if (emp[j].num > emp[j + 1].num)
            {
                temp = emp[j];      //emp[j] = temp;  修改
                emp[j] = emp[j + 1];
                emp[j + 1] = temp;
            }
        }
    }
    //冒泡排序
    ofstream infile("职工表");
    for (int i = 0; i <= 4; i++)
    {
        infile << emp[i].num << " " << emp[i].name << " " << emp[i].age << " " << emp[i].mon << endl;  //修改
    }
    infile.close();
    return 0;
}