正则表达式没有按预期工作 - PHP preg_match_all

Question

I have string which contains a variable in curly braces and I want to replace them with a value.

$text = 'Hi My Name is ##{Name}## and I am ##{Adjective}##';

preg_match_all('/{([^#]+)}/i', $text, $matches);
foreach ($matches[1] as $key => $value) {
    $text = str_replace('{' . $value . '}', 'SomeValue', $text);
}
print_r($matches[1]);
print_r(str_replace('##', '', $text));

OUTPUT

Array ( [0] => Name [1] => Adjective ) 
Hi My Name is SomeValue and I am SomeValue

But I am not able to handle deifferent variations of the string for example.

1. $text = 'Hi My Name is ##{Name}{Adjective}##'
2. $text = 'Hi My Name is ##{Name}and I am{Adjective}##'
3. $text = 'Hi My Name is ##{Name}, {Adjective}##'
4. $text = 'Hi My Name is ##{Name} {Adjective}##'

I would want the similar result in array output so that values can be replaced

 Array ( [0] => Name [1] => Adjective ) 

NOTE: I am able to ensure that '##' will always be present at the start and end of the curly braces, but not necessarily in between the braces e.g. point 1,2,3,4 above in example string.

Answer 1

I'd recommend using preg_replace_callback with the pattern /\{(.+?)}/ and a callback like this

$callback = function($matches) use (&$found) {
  $found[] = $matches[1];
  return 'SomeValue';
};

This will let you record the matches in the $found array while replacing the entire {Name}, {Adjective} with "SomeValue".

$found = [];
$newTxt = str_replace('##', '',
    preg_replace_callback('/\{(.+?)}/', $callback, $txt));

Demo here ~ https://eval.in/641827