dongshi2836 2012-11-20 09:46
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PHP:从类中的另一个函数调用变量

This is my class code:

class myClass
{

   public function myFunc()
   {
      $myvar   =  'Test str';
   }

   public function result()
   {
      echo myClass::myFunc()->$myvar;
   }
}

and I use this:

   $nCls = new myClass;
   $nCls->result();

To show Test str form myFunc() but nothing shown. I think the problem is :

echo myClass::myFunc()->$myvar;

Thanks for any help.

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5条回答 默认 最新

  • dsakktdog498483070 2012-11-20 09:49
    关注

    The problem is that you declare $myvar only in the scope of method myFunc(). That means it is not visible outside that method. Declare it as a class member instead:

    class myClass
    {
    
       private $myvar;
    
       public function myFunc()
       {
          $this->myvar   =  'Test str';
       }
    
       public function result()
       {
          echo myClass::myFunc()->$myvar;
       }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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