winform输出结果进行放大缩小

Question

 private void pictureBox1_Paint(object sender, PaintEventArgs e)
        {
            // 获取用户输入的矩形中心点、长和宽
            double centerX = Convert.ToDouble(textBox1.Text);
            double centerY = Convert.ToDouble(textBox2.Text);
            double width = Convert.ToDouble(textBox3.Text);
            double height = Convert.ToDouble(textBox4.Text);

            // 创建绘图对象
            Graphics g  = e.Graphics;
            g.Clear(Color.White);

            // 获取坐标轴原点的坐标
            double originX = pictureBox1.Width / 2.0 ;
            double originY = pictureBox1.Height / 2.0;

            // 绘制坐标轴
            Pen axisPen = new Pen(Color.Black, 2);
            g.DrawLine(axisPen, 0, (float)(pictureBox1.Height / 2.0), pictureBox1.Width, (float)(pictureBox1.Height / 2.0)); // 水平线
            g.DrawLine(axisPen, (float)(pictureBox1.Width / 2.0), pictureBox1.Height, (float)(pictureBox1.Width / 2.0), 0); // 垂直线

            // 绘制箭头
            Point[] arrow = new Point[3];
            arrow[0] = new Point(pictureBox1.Width - 10, pictureBox1.Height / 2 - 5);
            arrow[1] = new Point(pictureBox1.Width, pictureBox1.Height / 2);
            arrow[2] = new Point(pictureBox1.Width - 10, pictureBox1.Height / 2 + 5);
            g.FillPolygon(Brushes.Black, arrow); // 水平箭头
            arrow[0] = new Point(pictureBox1.Width / 2 - 5, 10);
            arrow[1] = new Point(pictureBox1.Width / 2, 0);
            arrow[2] = new Point(pictureBox1.Width / 2 + 5, 10);
            g.FillPolygon(Brushes.Black, arrow); // 垂直箭头

            // 计算矩形的四个顶点坐标
            //centerX = centerX + originX;
            //centerY = centerY + originY;
            double left = centerX - width / 2.0;
            double right = centerX + width / 2.0;
            double top = centerY - height / 2.0;
            double bottom = centerY + height / 2.0;

            // 绘制矩形
            Pen rectPen = new Pen(Color.Red, 2);
            g.DrawRectangle(rectPen, (float)(originX + left), (float)(originY - bottom), (float)width, (float)height);
        }
        private void pictureBox1_MouseWheel(object sender, MouseEventArgs e)
        {
            
            Rectangle rec = pictureBox1.DisplayRectangle;
            Point p = new Point(e.X, e.Y);
            int delta = e.Delta;
            double zoomFactor = 1.2; // 缩放因子
            if (delta < 0)
                zoomFactor = 1 / zoomFactor; // 向下滚动，缩小图像
            // 修改控件大小，缩放图像
            pictureBox1.Width = Convert.ToInt32(pictureBox1.Width * zoomFactor);
            pictureBox1.Height = Convert.ToInt32(pictureBox1.Height * zoomFactor);
            
            // 修改图像比例，缩放图像
            pictureBox1.Scale(new SizeF((float)zoomFactor, (float)zoomFactor));

            // 重新绘制图像
            pictureBox1.Invalidate();
        }

我这样可以将picturebox控件进行放大缩小，我想知道怎么才能只将绘制出的矩形进行放大缩小（类似于将坐标轴的刻度放大缩小，矩形随之改变），而不改变坐标系和控件的大小，我是初学者，求各位牛人指教一下。

Answer 1

该回答引用GPT:
要实现只将绘制出的矩形进行放大缩小，可以在pictureBox1_MouseWheel事件中添加以下代码：

// 获取用户输入的矩形中心点、长和宽
double centerX = Convert.ToDouble(textBox1.Text);
double centerY = Convert.ToDouble(textBox2.Text);
double width = Convert.ToDouble(textBox3.Text);
double height = Convert.ToDouble(textBox4.Text);

// 计算矩形的四个顶点坐标
double left = centerX - width / 2.0;
double right = centerX + width / 2.0;
double top = centerY - height / 2.0;
double bottom = centerY + height / 2.0;

// 根据鼠标滚轮滚动的距离，计算缩放因子
double zoomFactor = 1.2; // 缩放因子
if (delta < 0)
    zoomFactor = 1 / zoomFactor; // 向下滚动，缩小图像

// 根据缩放因子，计算缩放后的矩形的四个顶点坐标
double newLeft = left * zoomFactor;
double newRight = right * zoomFactor;
double newTop = top * zoomFactor;
double newBottom = bottom * zoomFactor;

// 绘制缩放后的矩形
Pen rectPen = new Pen(Color.Red, 2);
g.DrawRectangle(rectPen, (float)(originX + newLeft), (float)(originY - newBottom), (float)(newRight - newLeft), (float)(newBottom - newTop));

如还有疑问，可留言帮助解决。