关于#c语言#的问题：输出数组元素的格式为”%5d”

Question

int a[5 ][4 ]=2,5,-86,31 32,1,0,798 3,4,5,6 25,61,33,92 -51,21,37,96 这个数组中，一共有五行，怎样将任意两行交换，然后输出。输入格式为”%d%d”，输出数组元素的格式为”%5d”。

Answer 1

#include <stdio.h>

#define ROWS 5
#define COLS 4

void swap_rows(int arr[ROWS][COLS], int m, int n) {
    int temp[COLS];
    for (int i = 0; i < COLS; i++) {
        temp[i] = arr[m][i];
        arr[m][i] = arr[n][i];
        arr[n][i] = temp[i];
    }
}

int main() {
    int arr[ROWS][COLS] = {2,5,-86,31},{32,1,0,798},{3,4,5,6},{25,61,33,92},{-51,21,37,96}};
    printf("原始:\n");
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            printf("%2d ", arr[i][j]);
        }
        printf("\n");
    }
    printf("\n");
    int m, n;
    printf("输入m n");
    scanf("%d %d", &m, &n);
    swap_rows(arr, m - 1, n - 1);
    printf("交换后:\n");
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            printf("%2d ", arr[i][j]);
        }
        printf("\n");
    }
    return 0;
}