strstr中的第三个参数仅在PHP 5.3.0中有效

Question

Hello I want to get user from an email address,

eg: [e-mail] then output must be sajid

for this i use below mentioned code

$user = strstr($email, '@', true);

but an warning occur

Warning: Wrong parameter count for strstr() in /var/www/DataTable/dialog.php on line 3

& in php manul it is clearly define that the 3rd argument true is only valid for PHP 5.3.0

So is there any string function which could solve my problem?

Answer 1

$user = substr($email, 0, strpos($email, '@'));