检查++是否存在，如果不存在，则得到最近的

Question

[     number      -      title     ]
[        1        -        t1      ]
[        2        -        t2      ]
[        5        -        t3      ]
[       13        -        t4      ]
[       22        -        t5      ]

for this part $next_post = $number+1; each time i click for example on a button, Go a step forward, But when it reaches $number = 2; it will give me 404 error since there is no $number = 3; How am i supposed to type a query to check if the next number doesn't exist, And then jump directly to the nearest number.

Answer 1

Put your numbers in an array:

$numbers = [1, 2, 5, 13, 22];

Now you can use $next_post = $number[$i + 1];