关于#c语言#pta的问题，如何解决？

Question

问一下各位，c语言，在dev c++上没有问题，给的测试用例也都能通过，但pta一直显示有错误

#include <stdio.h>

int main() {
    int i, n, q = 0, a[2][6];
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        scanf("%d", &a[1][i]);
        q = 0;
        while (a[1][i]) {
            a[0][q] = a[1][i] % 10;
            a[1][i] /= 10;
            q++;
        }
        if (a[0][0] + a[0][1] + a[0][2] == a[0][3] + a[0][4] + a[0][5]) {
            printf("You are lucky!\n");
        } else {
            printf("Wish you good luck.\n");
        }
    }
    return 0;
}

Answer 1

供参考：

//一维数组就可以了

#include <stdio.h>
int main() {
    int i, n, q = 0, a[6], b; //修改
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        scanf("%d", &b);  //scanf("%d", &a[1][i]);
        q = 0;
        while (b) {      //while (a[1][i])
            a[q++] = b % 10;  //a[0][q] = a[1][i] % 10;
            b /= 10;    //a[1][i] /= 10;
                        //q++;
        }
        if (a[0] + a[1] + a[2] == a[3] + a[4] + a[5]) {
            printf("You are lucky!");
        }
        else {
            printf("Wish you good luck.");
        }
        if (i != n - 1)    //修改 最后一行无换行
            printf("\n");  //修改
    }
    return 0;
}


//二维数组这样改试试
#include <stdio.h>
#define N 101                  //修改 
int main() {
    int i, n, q = 0, a[2][N];  //a[2][6];
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        scanf("%d", &a[1][i]);
        q = 0;
        while (a[1][i]) {
            a[0][q++] = a[1][i] % 10;
            a[1][i] /= 10;
            //q++;
        }
        if (a[0][0] + a[0][1] + a[0][2] == a[0][3] + a[0][4] + a[0][5]) {
            printf("You are lucky!");
        }
        else {
            printf("Wish you good luck.");
        }
        if (i != n - 1)    //修改 最后一行无换行
            printf("\n");  //修改
    }
    return 0;
}