dongzhuo3059 2010-07-08 09:54
浏览 44
已采纳

在MySQL表中显示索引

If I define a MySQL index over two fields, how do I find out, which two belong together (using MySQL commands).

Here is an example table:

mysql> DESCRIBE lansuite_wiki_versions;
+-----------+-----------------------+------+-----+-------------------+-----------------------------+
| Field     | Type                  | Null | Key | Default           | Extra                       |
+-----------+-----------------------+------+-----+-------------------+-----------------------------+
| versionid | int(11)               | NO   | PRI | 0                 |                             |
| postid    | int(11)               | NO   | PRI | 0                 |                             |
| date      | timestamp             | NO   |     | CURRENT_TIMESTAMP | on update CURRENT_TIMESTAMP |
| userid    | mediumint(8) unsigned | NO   | MUL | 0                 |                             |
| text      | text                  | NO   | MUL | NULL              |                             |
| test1     | int(11)               | NO   | MUL | NULL              |                             |
| test2     | int(11)               | NO   |     | NULL              |                             |
+-----------+-----------------------+------+-----+-------------------+-----------------------------+
7 rows in set (0.00 sec)

This table has indexes defined over:

  • versionid + postid
  • userid
  • test1 + test2
  • text

I know this, because I have assigned them and see them in phpmyadmin. But I want to see it in my application as well. So I found this mySQL command:

mysql> SHOW INDEX FROM lansuite_wiki_versions;
+------------------------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table                  | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+------------------------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| lansuite_wiki_versions |          0 | PRIMARY  |            1 | versionid   | A         |        NULL |     NULL | NULL   |      | BTREE      |         |
| lansuite_wiki_versions |          0 | PRIMARY  |            2 | postid      | A         |         144 |     NULL | NULL   |      | BTREE      |         |
| lansuite_wiki_versions |          1 | userid   |            1 | userid      | A         |           4 |     NULL | NULL   |      | BTREE      |         |
| lansuite_wiki_versions |          1 | test     |            1 | test1       | A         |           1 |     NULL | NULL   |      | BTREE      |         |
| lansuite_wiki_versions |          1 | test     |            2 | test2       | A         |           1 |     NULL | NULL   |      | BTREE      |         |
| lansuite_wiki_versions |          1 | text     |            1 | text        | NULL      |           1 |     NULL | NULL   |      | FULLTEXT   |         |
+------------------------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
6 rows in set (0.00 sec)

But how do I see versionid + postid is connected? I can see Seq_in_index counting up. So can I rely on that versionid and postid form a common index, just because they are standing in rows next to each other in this output and the Seq_in_index countin up? Or is there an other command, that shows me which indexes are defined?

  • 写回答

3条回答 默认 最新

  • duanmei9980 2010-07-08 09:58
    关注

    The Key_name will be unique for each index; columns which are part of the same index will have the same name in this table.

    seq_in_index gives you the sequence.

    It may make more sense if you look at the INFORMATION_SCHEMA table containing indexes (look at documentation).

    I assume you are writing a tool to programmatically inspect the database structure.

    If you are a human and want to see the table structure, I recommend SHOW CREATE TABLE instead.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 请问为什么我配置IPsec后PC1 ping不通 PC2,抓包出来数据包也并没有被加密
  • ¥200 求博主教我搞定neo4j简易问答系统,有偿
  • ¥15 nginx的使用与作用
  • ¥100 关于#VijeoCitect#的问题,如何解决?(标签-ar|关键词-数据类型)
  • ¥15 一个矿井排水监控系统的plc梯形图,求各程序段都是什么意思
  • ¥50 安卓10如何在没有root权限的情况下设置开机自动启动指定app?
  • ¥15 ats2837 spi2从机的代码
  • ¥200 wsl2 vllm qwen1.5部署问题
  • ¥100 有偿求数字经济对经贸的影响机制的一个数学模型,弄不出来已经快要碎掉了
  • ¥15 数学建模数学建模需要