检查PHP中的数字范围

Question

I have a simple PHP script that is checking the range of a number. For some reason, once the number I am checking equals 100% the code does not work. Here is my code:

$percent_completed = '100%';                            

if ($percent_completed <= '20%') {
    $color = 'danger';
} elseif ($percent_completed >= '21%' && $percent_completed < '40%') {
    $color = 'warning';
} elseif ($percent_completed >= '40%' && $percent_completed < '60%') {
    $color = 'info';
} elseif ($percent_completed >= '60%' && $percent_completed < '80%') {
    $color = 'primary';
} elseif ($percent_completed >= '80%' && $percent_completed < '100%') {
    $color = 'default';
} else {
    $color = 'success';
}

echo $color;

All of the conditional checks above work just fine until $percent_completed is equal to 100%. For some reason it is set to 100% the $color that is printed out is danger. I am sure it is a simple fix but everything I have tried does not work.

Answer 1

Get rid of the % from your $percent_completed variable. It makes it as string which will give you different results than when comparing as a integer (for numbers).

$percent_completed = 100;                            

if ($percent_completed <= 20) {
    $color = 'danger';
} elseif ($percent_completed < 40) {
    $color = 'warning';
} elseif ($percent_completed < 60) {
    $color = 'info';
} elseif ($percent_completed < 80) {
    $color = 'primary';
} elseif ($percent_completed < 100) {
    $color = 'default';
} else {
    $color = 'success';
}

echo $color;