duanjuelian4640 2014-01-22 06:51
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MySQL返回结果在while循环中显示两次?

I have a database named as ps_megasearch_attributes. For that my database query is like this

CREATE TABLE IF NOT EXISTS `ps_megasearch_attributes` (
  `attribute_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `attribute_name` text NOT NULL,
  PRIMARY KEY (`attribute_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8  ;

--
-- Dumping data for table `ps_megasearch_attributes`
--

INSERT INTO `ps_megasearch_attributes` (`attribute_id`, `attribute_name`) VALUES
(1, 'Color');

Now to get the values from the database I have this code in php

<?php 
$attribute_name_fetch = mysqli_query($con,"SELECT `attribute_name` FROM `ps_megasearch_attributes` ORDER BY `attribute_id` DESC LIMIT 1 " );
while($attributes_list=mysqli_fetch_array($attribute_name_fetch )){
  foreach($attributes_list as $attribute_name) {
    echo $attribute_name;
  }
}

?>

But this one is showing the return result array two times. So can someone kindly tell me how to do this? Any help will be really appreciable.

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  • donglu5000 2014-01-22 06:54
    关注

    mysqli_fetch_array

    mysqli_result::fetch_array -- mysqli_fetch_array — Fetch a result row as an associative, a numeric array, or both

    You don't require foreach loop.

    while($attributes_list=mysqli_fetch_array($attribute_name_fetch )){
        echo $attributes_list['attribute_name']
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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