douraoyw194498 2019-07-21 02:08
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如何删除数组中的元素数组

I have two array. I want to remove if 2nd array exists in 1st array. For example

array1 = array ("apple","banana","papaya","watermelon","avocado");
array2 = array ("apple","avocado");

I want the output should be

Array ( [1] => banana [2] => papaya [3] => watermelon)

Here are some code that I'd tried.

foreach($array2 as $key){
    $keyToDelete = array_search($key, $array1);
    unset($array1[$keyToDelete]);
}
print_r($array1);

but the output is

Array ( [1] => banana [2] => papaya [3] => watermelon [4] =>avocado )

It only remove first element.

i also tried to do something like this

$result = array_diff($array1,$array2);
print_r($result);

but the output is it print all element in array1

Noted: I want the result need to be outside foreach loop

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3条回答 默认 最新

  • dongyisa6254 2019-07-21 02:14
    关注

    array_diff should be work.

    <?php
    
    $array1 = array ("apple","banana","papaya","watermelon","avocado");
    $array2 = array ("apple","avocado");
    
    $array_diff = array_diff($array1, $array2);
    
    print_r($array_diff);
    
    ?>
    

    DEMO

    output will be.

    Array ( [1] => banana [2] => papaya [3] => watermelon)
    

    You can also try below solution. result will be same.. using in_array Check if first array value not in the second tester that value in the new array 'final_result' for results.

    in_array support (PHP 4, PHP 5, PHP 7)

    $array1 = array ("apple","banana","papaya","watermelon","avocado");
    $array2 = array ("apple","avocado");
    
    $final_result = array();
    foreach($array1 as $value){
    
        if(!in_array($value, $array2)){
    
            $final_result[] = $value;
        }
    
    }
    
    print_r($final_result);
    
    ?>
    

    DEMO

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