PHP修剪内部功能

Question

I have the following simple PHP script:

<?php

    function generate($test_var, trim($test_var2)) {
        echo $test_var2;
    }

    generate('value 1', ' value2');

?>

It's giving the following error:

PHP Parse error:  syntax error, unexpected '(', expecting '&' or T_VARIABLE 
in ** on line 3

I can't figure out why trim can't be used in this context.

Answer 1

You simply can't call a function inside the argument list of the definition of another function^*. Perhaps you meant to do something like this:

function generate($test_var, $test_var2) {
    $test_var2 = trim($test_var2);
    echo $test_var2;
}

^{* Note that you can use the array language construct when declaring the default value of parameter, although this isn't a function.}

Further Reading

• Function arguments