duandange7480 2013-09-05 04:34
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无法使用MySQLi_connect连接到MySQL

I am trying to fetch results using ajax,php and MySql. However I am getting following errors on my server side script.

Warning: mysqli_select_db() expects parameter 1 to be mysqli, resource given in D:\htdocs\classes\xxx on line 10

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource

The server side code is as follows:

<?php
$q = intval($_GET['q']);

$con= mysqli_connect("localhost","root","abcd123") or die ("could not connect to mysql"); 

mysqli_select_db($con,"payrolldb001") or die ("no database"); 

$sql="SELECT substationid,substationcode FROM wms_substation WHERE assemblylineid = '".$q."'";

$result = mysqli_query($con,$sql);


echo "<select>";
while($row = mysqli_fetch_array($result))
  {
  echo "here";
  echo "<option>". $row['substationcode'] . "</option>";
  }
echo "</select>";

mysqli_close($con);
?>

I can not figure out where am i going wrong.Please help.

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2条回答 默认 最新

  • dongshan7708 2013-09-05 04:37
    关注

    Try this,

    $con = mysqli_connect("localhost","root","abcd123","payrolldb001") or die("Error " . mysqli_error($con));
    $sql="SELECT substationid,substationcode FROM wms_substation WHERE assemblylineid = '".$q."'";
    
    $result = mysqli_query($con,$sql);
    ...
    

    Or

    $con= mysqli_connect("localhost","root","abcd123") or die ("could not connect to mysql"); 
    
    mysqli_select_db($con,"payrolldb001") or die ("no database"); 
    

    Read mysqli_select_db

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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