如何以良好的格式显示剩余日期？

Question

I am creating a value that shows me the remaining time from a date until now:

$date=date_create(date('Y-m-d H:i:s', strtotime($mydate)));
$curdate=date_create(date("Y-m-d H:i:s"));
$diff=date_diff($date,$curdate);
$diff1= $diff->format("%y years %m months %d days");

The result in this case is: 0 years 0 months 27 days

What I would like to do is, show only years or months if they are not 0. So in this case I would only like to get the result 27 days. And if it is only one day left, then it shows 1 days but it should show 1 day (so if the result is 1 show singular).

I tried something like this, but it didn't work:

$diff1= $diff->format(if("%y" !=0){"%y years"}); if("%m" !=0){"%m months"}) %d days");

Answer 1

date_diff returns an instance of the DateInterval class which has the class variables $y, $m and $d for the corresponding years, months and days.

As such what you were trying to achieve can still be done using these variables:

$diff=date_diff($date,$curdate);
$format = '';
if ($diff->y > 0) {
     $format = '%y years';
} else if ($diff->m > 0) {
     $format = '%m months';
} else {
     $format = '%d days';
}
$diff1 = $diff->format($format);

The elimination of the s in years/months/days is left up to the OP.

(edited)

In this case only one category will printed, but to get more than one at a time, modify the 'if-else' to individual 'if' and concatenation with previous categories,

if ($diff->y > 0) {
     $format = '%y years ';
}
if ($diff->m > 0) {
     $format .= '%m months ';
}
if ($diff->d > 0) {
     $format .= '%d days';
}