down00111 2010-09-08 15:01
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将值从一种形式传递到另一种形式 - 一种奇怪的情况

Please have a look to the following code:

<?php

  $nomeDominio='';

  if (isset($_GET['infoDominio']))
  {          
      $nomeDominio = $_GET['nomeDominio'];
      echo "I'm getting ".$nomeDominio;
  }

  if (isset($_POST['atualizarDominio']))
  {
      echo "I'm posting ".$nomeDominio;
  }

?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>

    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>Test Case 99</title>
    </head>

    <body>

        <form name="infoDominio" action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>"  method="get">

            <input id="nome_dominio" type="text" name="nomeDominio" value="<?php echo $nomeDominio; ?>"/>
            <br />
            <button name="infoDominio" type="submit">Obtem informacao</button>

        </form>

        <form action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>" name="atualizarDominio" method="post">

            <input type="hidden" value="<?php echo $nomeDominio ?>" name="nome-dominio"/>
            <br />
            <button type="submit" name="atualizarDominio">atualizar domínio</button>

        </form>

    </body>

</html>

You can copy/paste - it will serve as test case.

Like this, IF we get and then we post: The value from GET WILL NOT pass into POST.

The thing is: If we just change the action= property of the second form element to, instead of having the $_SERVER['PHP_SELF'], to have just action=""; you will notice that the value WILL pass.

My question is: Why?

ADDITIONAL NOTE: This is not something to solve. Instead, this is something to understand why is it happening this way. Why, if we change the action on the second form to action="", the value stored in $nomeDominio pass from one conditional into another? The code sample can be used by itself, so you can perfectly test this very easily and see what I'm talking about.

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4条回答 默认 最新

  • dongmin3754 2010-09-08 15:06
    关注
     {          
          $nomeDominio = $_GET['nomeDominio'];
          echo "I'm getting ".$nomeDominio;
      }
    
      if (isset($_POST['atualizarDominio']))
      {
          $nomeDominio = $_POST['nomeDominio']; //THIS HERE
          echo "I'm posting ".$nomeDominio;
      }
    

    you are missing the line with comment THIS HERE

    You wanted to pass the _GET['nomeDominio'] from the first form to a hidden field of the second form right? Then when we submit the SECOND form you echo nomeDominio's value again (from the second form's hidden field). You where missing and assignement in the $_POST: $nomeDominio = $_POST['nomeDominio'];

    There you go. If you do not undesrtand I do not know how to say differently.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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